Bone Collector
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 55245 Accepted Submission(s): 23100
Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1
Sample Output
14
#include<iostream>
#include<cstdio>
#include<string.h>
#include<algorithm>
using namespace std;
int c[1005];//容量
int w[1005];//价值
int f[1005];
int main(){
int T,n,V;
scanf("%d",&T);
while(T--){
memset(c,0,sizeof(c));
memset(w,0,sizeof(w));
memset(f,0,sizeof(f));
scanf("%d%d",&n,&V);
for(int i=1;i<=n;i++)
scanf("%d",&w[i]);
for(int i=1;i<=n;i++)
scanf("%d",&c[i]);
for(int i=1;i<=n;i++)
for(int v=V;v>=c[i];v--)
f[v]=max(f[v],f[v-c[i]]+w[i]);
printf("%d\n",f[V]);
}
}